Question

If tan a= 1 /root 3and sin b 1/root 2
find a+b​

Answer 1

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

●$tanA=\frac{1}{\sqrt{3}}$

●$sinB=\frac{1}{\sqrt{2}}$⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

●(A+B)=??? ⠀⠀⠀⠀

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

⏩$tanA=\frac{1}{\sqrt{3}}$

⏩$tanA=tan30°$⠀⠀⠀

⭐$\boxed{\pink{A=30°}}$

Then,

⏭$sinB=\frac{1}{\sqrt{2}}$⠀

⏭$sinB=sin45°$

⭐$\boxed{\pink{B=45°}}$

So.......

A+B=30°+45°

A+B=75°

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

♥️${\underline{\underbrace{\mathcal\color{gold}{(A+B)=75°}}}}$

⠀⠀⠀⠀

Answer 2

Given:

$◈tan \: a = \frac{1}{ \sqrt{3} } \\ \\ ◈sin \: b = \frac{1}{ \sqrt{2} }$

To find:

a+b

Solution:

$\sf \large Tan \: a = \frac{1}{ \sqrt{3} }$

$\sf \large As \: we \: know \: that \: tan \: 30 \degree = \frac{1}{ \sqrt{3} }$

So a is 30°

$\sf \large Sin \: b = \frac{1}{ \sqrt{2} }$

$\sf \large As \: we \: know \: that \: sin \: 45 \degree = \frac{1}{ \sqrt{2} }$

So b is 45°

(a+b)

30°+45°

75°