Question

Find three consecutive number such that twice the first three times the second and four times the third together make 191

Answer 1

the three numbers are 20 ,21,22

Answer 2

Answer:

Description for Correct answer:

Let the first no. be 'a'

According to question

2a+3(a+1)+4(a+2)=191

2a+3a+3+4a+8=191

9a=191−11

a=1809=20

No. are (20,21,22)