What is the mass (in grams) of 9.48 × 1024 molecules of methanol (ch3oh)?
Answers
Answered by
1
C = 12
H3 = 3x1 = 3
O = 16
H =1
Total 32g So we know 6.02x10^23 molecules weigh 32g
So 1 molecule weighs 32/6.02x10^23 g
So 9.95x10^24 molecules weighs 9.95x10^24 x (32/6.02x10^23) = 9.95x32x10/6.02=99.5x32/6.02=528.90g
H3 = 3x1 = 3
O = 16
H =1
Total 32g So we know 6.02x10^23 molecules weigh 32g
So 1 molecule weighs 32/6.02x10^23 g
So 9.95x10^24 molecules weighs 9.95x10^24 x (32/6.02x10^23) = 9.95x32x10/6.02=99.5x32/6.02=528.90g
Similar questions