Question

Find three consecutive number such that when the least number is subtracted from the sum of the other two numbers the result is 726

Answer 1

Here's your answer buddy :-

Let the three consecutive numbers be :-

x, x+1, x+2

Now, the sum of the second and third number is 726 greater then the first number.

Thus,

(x+1+x+2) - x = 726

2x + 3 - x = 726

2x = 726 - 3

x = 723/2

x = 361.5

$\bold{ \underline{ \therefore \: the \: three \: numbers \: are \: 361.5, \: 362.5 \: and \: 363.5}}$

Hope it helps