Question

find three consecutive numbers such that if they are divided by 10,17,and 26 respectively,the sum of their quotients will be 10.

Answer 1

Let the consecutive numbers = x , x + 1, x + 2 

now acc. to question
 x/10 + (x+1)/17 +(x+2)/26 =10

on solving above expression
we get
10*4420=872*x+600
⇒872x=43600
⇒x=50.........

Answer 2

Answer:

50 , 51, 52 this is the answer