Math, asked by harrysdab, 8 months ago


Find three consecutive numbers such that sum of twice the first, thrice the second and four
times the third makes 146.​

Answers

Answered by Geetu18
8

Answer:

15,16,17

Step-by-step explanation:

let the no. = x-1, x , x+1

A.T.Q

2( x-1) + 3x + 4( x+1) =146

2x -2 + 3x +4x+4 = 146

9x + 2 = 146

9x = 146-2

x = 144/9

x= 16

hence, no. are 15, 16, 17

Answered by aditi4590
2

Step-by-step explanation:

numbers are 15,16,17

please have me thanks

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