Question

IN
2N
45° | 45°
23. There are four forces acting o
n a
particle P, which then continues
to remain at rest. Evaluate the
forces F, and F,
90°​

Answer 1

Here is your answer:

Explanation:

Applying equilibrium conditions.

Take right positive. ∑F x  =0  

F  1  +1sin45°  −2sin45° = 0

F  1   = 2sin45°  −1sin45°

F1 = 2/ √2 - 1/ √2 = 1 / √2 N

Take upward positive ∑F  y  = 0

1cos45°  + 2sin45° - F2 = 0

F2 = 2 / √2 + 1 / √2

f2  = 2+1 / √2 = 3 / √2 N

Hence F1 = 1 / √2 N and F2 = 3 / √2 N