Question

find three consecutive numbers such that the sum of second and third number exceefs first by 28​

Answer 1

Answer:

Let the first consecutive number = x,

Second consecutive number = x + 1

and Third consecutive number = x + 2

According to the condition,

x+x+1=15+x+2x+x+1=15+x+2

⇒2x+1=17+x⇒2x+1=17+x

⇒2x-x=17-1⇒2x−x=17−1

⇒x=16⇒x=16

∴ The first natural number = x = 16

Second natural number = x+1 = 16+1 = 17

Third natural number = x +2 = 16 + 2=18

Hence, the three consecutive natural numbers are 16, 17 and 18.