Question

Find three consecutive numbers such that the sum of second and third number exceeds the first by fourteen

Answer 1

Given info : Three consecutive numbers such that the sum of second and third number exceeds the first by fourteen.

solution : we have to find all three consecutive numbers.

let x , x + 1 and x + 2 are three consecutive numbers.

a/c to question,

second + third = first + 14

⇒x + 1 + x + 2 = x + 14

⇒2x + 3 = x + 14

⇒x = 14 - 3 = 11

therefore first number = x = 11

second number = x + 1 = 11 + 1 = 12

and third number = x + 2 = 11 + 2 = 13.

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