Question

Find three consecutive numbers such that the sum of the second and the third number exceeds the first
by 14.

Answer 1

Answer:

Let the first number be x

Second be x+1 and third be x+2

According to the question :

(X+1+X+2)-X=14

2X+3-X=14

X=14-3

X=11

THEREFORE THE NUMBERS ARE 11,12 AND 13

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the number be x

Second be x+1 and third be x+2

According to the question :

(X+1+X+2)-X=14

2X+3-X=14

X=14-3

X=11

THEREFORE THE NUMBERS ARE 11,12 AND 13

hope this helps you out and please mark me as BRAINLIEST