Find three consecutive numbers such that the sum of the first and third is 118
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1
let the three consecutive nos are x-1,x,x+1
the sum of the first and third is 118
so x-1+x+1=118
or 2x=118
or x=118/2=59
so the three consecutive nos are 58,59,60
the sum of the first and third is 118
so x-1+x+1=118
or 2x=118
or x=118/2=59
so the three consecutive nos are 58,59,60
Answered by
2
Define x:
Let the first number be x
The second number is x + 1 and third number is x + 2
Solve x:
Sum of the first and the third is 118
x + (x + 2) = 118
x + x + 2 = 118
2x + 2 = 118
2x = 116
x = 58
Find the numbers:
First number = x = 58
Second number = x + 1 = 58 + 1 = 59
Third number = x + 2 = 58 + 2 = 60
Answer: The 3 numbers are 58, 59 and 60
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