find three consecutive numbers whose sum is 1200000
Answers
Answered by
5
Answer:
ur answer is 399999, 400000 and 400001.
Answered by
3
Answer:
Let three consecutive numbers are x,x+1 and x+2
ATQ,
x+x+1+x+2=1200000
3x+3=1200000
3x=1200000-3
x=1199997÷3
x=399999
So consecutive no. are:
x=399999
x+1=399999+1
=400000
x+2=399999+2
=400001
Hope it helps you!
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