Question

find three consecutive numbers whose sum is 147

Answer 1

Hey Buddy here is your answer,

Consider that the numbers are in an arithmetic sequence, where a is the first term and d is the common difference

In this case, the common difference is 1

a+a+d+a+2d=147

3a+3d=147

3a=144

a=48

So numbers are 48,49,50 (Ans)

HOPE THIS HELPS YOU. PLEASE MARK ME AS BRAINLIEST!!!!

Answer 2

SALUT AMIS !!



Three consecutive numbers = x, x + 1, x + 2

Sum = 147

x + x + 1 + x + 2 = 147

3x + 3 = 147

3x = 147 - 3

3x = 144

x = 144 / 3

× = 48

===>>The 3 consecutive numbers are = 48, 49,50

VERIFICATION :



50+48+49 = 147


Hope it helps !!