Find three consecutive numbers whose sum is 33
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Answered by
9
Let first number is X then other two are x+1 and x+2 respectively
According to question ,
X+(x+1)+(x+2) = 33
3x +3 = 33
3x = 30
x = 10
x+1 = 11
X+2 = 12
Answered by
2
Answer:
10,11 and 12
Step-by-step explanation:
Let the numbers be x, (x+1) and (x+2)
So, now the equation is been formed x+x+1+x+2= 33
now solve it, 3x+3= 33
Now take it ti the right hand side, the it will become negative.
So. 3x= 33-3
3x= 30 now, transpose 3 towards the right hand side, then it become division.
so, x= 30/3
x= 10
now,we have to find the numbers, so reme,ber the equations x, x+1 and x+2
so the first number is 10
second number is (10+1)= 11
third number is (10+2) = 12
Hence i Prooved My Answer!!!!
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