Math, asked by ish10808, 10 months ago

Find three consecutive numbers whose sum is 33

Answers

Answered by Anonymous
9

Let first number is X then other two are x+1 and x+2 respectively

According to question ,

X+(x+1)+(x+2) = 33

3x +3 = 33

3x = 30

x = 10

x+1 = 11

X+2 = 12

Answered by adhirajranjan2607
2

Answer:

10,11 and 12

Step-by-step explanation:

Let the numbers be x, (x+1) and (x+2)

So, now the equation is been formed x+x+1+x+2= 33

now solve it, 3x+3= 33

Now take it ti the right hand side, the it will become negative.

So. 3x= 33-3

3x= 30 now, transpose 3 towards the right hand side, then it become division.

so, x= 30/3

x= 10

now,we have to find the numbers, so reme,ber the equations x, x+1 and x+2

so the first number is 10

second number is (10+1)= 11

third number is (10+2) = 12

Hence i Prooved My Answer!!!!

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