Question

Find three consecutive numbers whose sum is 404.​

Answer 1

let the consecutive numbers are x, x+1, x+2

             According to question:

      x+x+1+x+2 = 404

     3x + 3 = 404

         3x = 404 - 3

       3x = 401

          x = 401/3 = 133.6  

     x + 1 = 133.6 +1 = 134.6

   x+2 = 133.6 +2 = 135.6

The 3 consecutive integers whose sum is 404 are 133.6 , 134.6 , 135.6

 ( this answer is in approx. )