find three consecutive numbers whose sum s -72
Answers
STEP 1: Define x:
Let the smallest number be x
The other two numbers are (x + 1) and (x + 2)
.
STEP 2: Form equation:
The sum is -72
x + (x + 1) + (x + 2) = -72
.
STEP 3: Solve x:
x + (x + 1) + (x + 2) = -72
x + x + 1 + x + 2 = -72
3x + 3 = -72
3x = -75
x = -25
.
STEP 4: Find the numbers:
Smallest number = x = -25
2nd number = x + 1 = -25 + 1 = -24
3rd number = x + 2 = -25 + 2 = -23
.
Answer: The 3 numbers are -25, -24 and -23
Hey there !
Solution:
Let the three consecutive numbers be denoted as:
( x - 1 ), ( x ), ( x + 1 )
So given that their sum is ( -72 )
Hence on adding the terms we get,
=> x + x - 1 + x + 1 = -72
=> 3x = -72
=> x = -72 / 3
=> x = -24
Hence the other numbers are ( x - 1 ) = -24 -1 = -25 , ( x + 1 ) = - 24 + 1 = - 23.
Hence the numbers are -23, -24, -25.
Hope my answer helped !