find three consecutive odd integers such that the sum of the first ,two times second ,and three times third is 70
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Let the numbers are x, x+1,x+2
Two times second=2(x+1)
Three times third =3(x+2)
Their sum=70
X+2x+2+3x+6=70
6x+8=70
6x=70-8
6x=62
X=62/6=10.3=10
Two times second=2(x+1)
Three times third =3(x+2)
Their sum=70
X+2x+2+3x+6=70
6x+8=70
6x=70-8
6x=62
X=62/6=10.3=10
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