find three consecutive odd number whose sum is 147
Answers
Answered by
35
let 3 consecutive odd nos
x+1. x+3 x+5=147
3x+9=147
3x=147-9
x=46.
so 46+1=47
46+3=49
46+5=51
x+1. x+3 x+5=147
3x+9=147
3x=147-9
x=46.
so 46+1=47
46+3=49
46+5=51
Answered by
5
we know that the numbers 2x + 1 , 2x + 3 and 2x + 5 will always remain odd numbers hence 47, 49 and 51 are the consecutive odd numbers whose sum is 147
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