Find three consecutive odd number whose sum is 9000
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Step-by-step explanation:
Which means that the first number is 2999, the second number is 2999 + 1 and the third number is 2999 + 2. Therefore, three consecutive integers that add up to 9000 are 2999, 3000, and 3001.
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(x+1)(x+3)(x+5)= 9000
now
x^2+3x+x+3(x+5)=9000
(x^2+4x+3)x+5=9000
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