find three consecutive odd numbers when three times of their sum is 5 more than 8 times the middle number.
Answers
Answered by
29
let the nos. be x, x+2, x+4
3(x+x+2+x+4)=5+ 8*(x+2)
3(3x+6) = 5+ 8x + 16
9x + 18 = 21 + 8x
9x - 8x = 21 - 18
x = 3
So the nos. are 3, 5, 7
3(x+x+2+x+4)=5+ 8*(x+2)
3(3x+6) = 5+ 8x + 16
9x + 18 = 21 + 8x
9x - 8x = 21 - 18
x = 3
So the nos. are 3, 5, 7
sanjana7358:
thankyou so much
Similar questions