Question

Solve it i will mark u brainliest of its correct

Answer 1

since
(x+y)=1,

(x+y)²=1²,

x²+y²+2xy=1,

x²+y²=1-2xy,

(x²+y²)²=(1-2xy)²,

x⁴+y⁴+2x²y²=1+4x²y²-4xy,

19+2x²y²-4x²y²=1-4xy,

19-2x²y²=1-4xy,

19-1=2x²y²-4xy,

18=2(x²y²-2xy),

then
x²y²-2xy=18/2=9

Answer 2

Hope it helps you
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(X+y)^2=x^2+y^2+2xy
1=x^2+y^2+2xy

X^2+y^2=1-2xy

(X^2+y^2)^2=x^4+y^4+2x^2y^2

(1-2xy)^2=19+2x^2y^2

1+4x^2y^2-4xy=19+2x^2y^2

2x^2y^2-4xy=18

2(x^2y^2-2xy)=18

x^2y^2-2xy=18÷2=9
Hope it helps you
Please mark me as the brainliest