Question

Find three consecutive odd numbers whose sum equals 741.​

Answer 1

Let the first odd no- x

Then, the second odd no- (x+2)

Then, the third odd no- x+4

=(x)+(x+2)+(x+4)= 741

= 3x+6= 741

=3x= 741-6= 735

=x= 735/3= 245

So, the three numbers are

x= 245

(x+2) = 245+2= 257

(x+4)= 245+4= 259

Answer 2

Answer:

let the no.'s be x, x+2,x+4

(x)+(x+2)+(x+4) = 741

3x+6=741

3x= 741-6

3x= 735

x=735/3

x= 245

so the first no. is 245

then,

x+2= 245+2=247

×+4=245+4=249

Ans- So, the no.'s are 245,247,249