Question

Find three consecutive odd numbers whose sum is 147.

Answer 1

Answer: 47, 49 & 51.

Step-by-step explanation:

Let the required numbers be (2x + 1), (2x + 3) and (2x + 5).

ATQ,

(2x+1) + (2x+3) + (2x+5) = 147.

> 6x + 9 = 147

> 6x = 147 - 9

> 6x = 138

> x = 138/6 = 23 (2x = 23 *2 = 46)

Hence, the numbers are (46+1), (46+3) and (46+5) = 47, 49 and 51

Answer 2

Given:

Find three consecutive odd numbers whose sum is 147.

To find:

Three consecutive odd numbers.

Solution :

Let 3 consecutive odd nos

x+1, x+3, x+5.

According to the given question:

=> x+1, x+3, x+5=147

=> 3x+9=147

=> 3x=147-9

=> 3x = 138

=> x = 138/3

=> x = 46  

The three consecutive odd numbers are :

=>  x+1 = 46+1=47

=> x+3 = 46+3=49

=> x=5 = 46+5=51