Question

find three consecutive odd numbers whose sum is 147

Answer 1

Let the three consecutive odd no. Be (x+1) (x+3) (x+5) then their sum is 147.
(x+1)+(x+3)+(x+5)=147----(1)
3x+9=147
X=46 after this put this value of x in eq(1) uh get 147

Answer 2

Step-by-step explanation:

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