Find three consecutive odd numbers whose sum is 147 and are we going to use x+1,x+3, x+5
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Answered by
1
(x+1)+(x+3)+(x+5)=147
3x+9=147
3x=138
x=46
x+1=47
x+3=49
x+5=51
3x+9=147
3x=138
x=46
x+1=47
x+3=49
x+5=51
Answered by
0
rusty885444446848685886r
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