find three consecutive odd numbers whose sum is 447
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Answered by
2
Answer:
therefore, three consecutive integers that add up to 447 are 148 , 149 , and 150
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Answered by
0
ANSWER:-
148, 149, 150
EXPLANATION:-
Let the three consecutive numbers be X, X+1, X+2
According to the question,
x+(x+1)+(x+2)=447
3x + 3 = 447
3x= 447-3
3x=444
x=444/3
x=148
so the required three consicutive no.s are :-
148, 148+1, 148+2
=148,149 , 150
HOPE IT HELPS.......
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