Question

find three consecutive positive even integers whose sum is 90

Answer 1

first no n
second no n+2
3rd no n+4


a.t.q
n+(n+2)+(n+4)=90
=3n +6=90
=3n=90-6
=3n=84
=n=84/3
=n=28
first number 28 second number n+ 2 is equal to 30 and thirdnumber n + 4 is equal to 32

Answer 2

Hey mate here is your answer ⤵⤵⤵

Let the three consecutive integers be x,x+2 and x+4

Now ,According to question, sum =90

$\implies$x+x+2+x+4=90

$\implies$x+x+x=90-6

$\implies$3x=84

$\implies$x=$\cancel{\frac{84}{3}}$

$\therefore$x=28

Hence the three even integers are x ,x+2,x+4
I.e.28,28+2,28+4

I.e. 28,30 and 32

❤hope it helps you ❤

♠Thanks for question ♠