Question

Find three consecutive term of an A.P. whose sum is 24 and product is 312

Answer 1

Answer:

Step-by-step explanation:

Let the three numbers in A.P. be a – d, a, and a + d.

According to the question :-

(a – d) + (a) + (a + d) = 24 ----- (1)

=) 3a = 24

=) a = 8

(a – d) a (a + d) = 440 ---- (2)

=) (8 – d) (8) (8 + d) = 440

=) (8 – d) (8 + d) = 55

=) 64 – d2 = 55

=)  d2 = 64 – 55 = 9

=)  d = ± 3

Therefore, when d = 3, the numbers are 5, 8, and 11 and when d = –3, the numbers are 11, 8, and 5.

So, the three numbers are 5, 8, and 11.