Question

find three consecutive terms in A.P whose sum is 9 and the product of their cubes is 3375
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Answer 1

Step-by-step explanation:

Given Find three consecutive terms in A.P whose sum is 9 and the product of their cubes is 3375

• Let (a -d), a and (a + d) be 3 consecutive terms in an A.P
• According to question
• So a – d + a + a + d = 9
• 3a = 9
• Or a = 3
• Also [a – d x  a x a + d)]^3 = 15^3
• So (a – d) a (a + d) = 15
• Now a = 3, substituting we get
• (3 – d)3(3 + d) = 15
• 3 (3^2 – d^2) = 15
• (9 – d^2) = 5
• Or d^2 = 4
• Or d = +-2
• Now a – d = 3 – 2 = 1 and a + d = 3 + 2 = 5
• Or a – d = 3 + 2 = 5 and a + d = 3 -2 = 1

So the consecutive terms in an A.P are (1,3,5) or (5,3,1)

Reference link will be

https://brainly.in/question/13391481