Question

Find three consecutive whole numbers whose sum is more than 45 and less than 54

Answer 1

Let the number is x, x+1, x+2
x+x+1+x+2 > 45
3x+3 > 45
3x > 42
x > 14
then
Ans is: 15,16,17

Answer 2

Answer:

The three whole consecutive numbers are either 15, 16, 17 or 16, 17, 18.

Step-by-step explanation:

Let the three consecutive whole numbers are x, x+1, x+2.

It is given that their sum is more than 45 and less than 54.

$45<x+x+1+x+2<54$

$45<3x+3<54$

Subtract 3 from each side.

$45-3<3x+3-3<54-3$

$42<3x<51$

Divide each side by 3.

$14<x<17$

The value of is more than 14 and less than 17. It means the value of x is either 15 or 16.

If x=15, then the three consecutive whole number are 15, 16, 17.

If x=16, then the three consecutive whole number are 16, 17, 18.

Therefore the three whole consecutive numbers are either 15, 16, 17 or 16, 17, 18.