Question

find three different solutions of the each of the following eqautions 3x+4y=7​

Answer 1

Answer:

Given equation is 3x+4y=7

If x=1 put in equation we get

(i)3×1+4y=7

⇒3+4y=7

⇒4y=7−3

⇒4y=4

⇒y=1

(1,1)

If x=2 put in equation we get

(i)3×2+4y=7

⇒6+4y=7

⇒4y=7−6

⇒4y=1

⇒y=  1/4

(2,1/4)

If x=3 put in equation we get

(iii)3×3+4y=7

⇒9+4y=7

⇒4y=7−9

⇒4y=−2

⇒y=−  2/4

     = -0.5

(3,−  0/5)

Answer 2

Answer:

solutions are (1,1) hope it helps