Question

Find three number in ap.Whose sum is 15 and whose product is 105

Answer 1

Answer:

let three numbers are a-d, a, a+d

a-d+a+a+d=3a=15

a=5

(a-d)a(a+d)=(5-d)*5*(5+d)=105

5(25-d"2)=105

125-105=5d"2

5d"2=20

d"2=4

d=2

three numbers are 3, 5, 7

Step-by-step explanation:

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Answer 2

Answer:

The three Terms will be 3 , 5 and 7

Step-by-step explanation:

Let the three terms be (a+d)(a)(a-d)

Sum will be 3a = 15

a=5

Product will be

(a^2 -b^2)a = 105

(25-d^2)5=105

d^2=4

d=+-2

Three terms were

(a+d)(a)(a-d)

Put the values of a and d

Three terms are 7,5 and 3.

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