Question

Find three number in ap whose sum is 6 and the product is - 24

Answer 1

Answer:

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Answer 2

✨✨✨✨ANSWER✨✨✨✨

• Let the three numbers are (a-d),a,(a+d)
• now .....

$(a - d) + a + (a + d) = 6 \\ 3a = 6 \\ a = \frac{6}{3 } \\ a = 2 \: \: \: \: \\ now \: \\ (a - d) \times a \times (a + d) = - 24 \\ (a {}^{2} - d {}^{2} ) = \frac{ - 24}{a} \\ (2 {}^{2} - d {}^{2} ) = \frac{ - 24}{2} \\ d {}^{2} = 4 + 12 \\ d = \sqrt{16} \\ d = 4 \: \: \\ therefore \: the \: numbers \: are \\ (2 - 4) \: ,2 \: ,(2 + 4) \\ - 2 \: ,\: 2 \:, \: 6$

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