find three numbers in ap whose sum is 15 and product is 105
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x+y+z=15
xyz=105
the nunbers are in the form of a-d,a,a+d(a is the first term ,d is the common diffrence)
x+y+z=a-d+a+a+d=3a=15
⇒a=5
xyz=(a-d)(a+d)a=(a-d)^2*a=(a^2-d^2)a=105
substuting the value of a we get ...
(5^2-d^2)5=25-d^2=21
d^2=25-21=4
d=⌈4=2
⇒the terms are
5-2,5,5+2=3,5,7
xyz=105
the nunbers are in the form of a-d,a,a+d(a is the first term ,d is the common diffrence)
x+y+z=a-d+a+a+d=3a=15
⇒a=5
xyz=(a-d)(a+d)a=(a-d)^2*a=(a^2-d^2)a=105
substuting the value of a we get ...
(5^2-d^2)5=25-d^2=21
d^2=25-21=4
d=⌈4=2
⇒the terms are
5-2,5,5+2=3,5,7
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