Find three numbers in ap whsoe sum is 18 and product is 66
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11.6.1=66and11+6+1=18
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let the three numbers in A.P. be a-d ,a, a+d . So sum of these three numbers is 18=> a+d+a+a-d =18 => 3a=18 => a =6 . Product of these three numbers is 66 => (a-d)a(a+d) =66 =>
So the numbers are 6+5,6,6-5 => 11,6,1 .
So the numbers are 6+5,6,6-5 => 11,6,1 .
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