Question

Rationalise the denominator

$\frac{ \sqrt{3} }{ \sqrt{7} - \sqrt{3} }$

Answer 1

√3/√7-√3
=√3(√7+√3)/(√7-√3)(√7+√3)
=(√21+3)/7-3
=(√21+3)/4..

Answer 2

Hola Mate!!

Your answer :-

$= > \frac{ \sqrt{3} }{ \sqrt{7} - \sqrt{3} } \\ \\ = > \frac{ \sqrt{3} }{ \sqrt{7 } - \sqrt{3} } \times \frac{ \sqrt{7} + \sqrt{3} }{ \sqrt{7 } + \sqrt{3} } \\ \\ = > \frac{ \sqrt{3} ( \sqrt{7} + \sqrt{3} )}{ {( \sqrt{7} )}^{2} - {( \sqrt{3} )}^{2} } \\ \\ = > \frac{ \sqrt{21 } + 3}{7 - 3} \\ \\ = > \frac{ \sqrt{21} + 3 }{4}$

☆ Hope it helps ☆