Math, asked by sahiljavid7301, 11 months ago

Find three numbers in the ratio 2:3:5 ,the sum of whose squares is 608

Answers

Answered by raji8115
1

8 ,12 ,20 are the required numbers

64 + 144+ 400 = 608

Just do it by hit and trail method

Answered by sajisharoon
1

Answer:

32, 48, 50.

Step-by-step explanation:

The unknown number is - 2²x + 3²x + 5²x = 608

4x + 9x + 25x = 608

38x = 608

x = 608/38

x = 16

x = √16 = 4

Hence, the three number are : - 2x = 2 × 4 = 8

                                                     3x = 3 × 4 = 12

                                                     5x = 5 × 4 = 20

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