Question

Five years ago, the age of a man was seven times the




age of his son. The age of the man will be three times




the age of his son in five years from now. The present




age of the man and his son, respectively are:

Answer 1

$\huge\bold\red{SOLUTION}$$\bold\purple{♡FollowMe♡}$

Let the age of son be x and father by y

Case 1.

y-5=7(x-5)

y = 7x-35+5

y=7x-30

Case 2

y+5 = 3(x+5)

7x-30+5=3x+15

4x=15+25

x=40

x=10

y=70-30

y=40

Thus age of father is 40 years and son is 10 years

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HOPE IT HELPS...