Find three solutions of linear equation 7x-5y=35 in two variables.
Answers
Answered by
72
x=0
-5y=35
y=-7(0,-7)
y=0
7x=35
x=5(5,0)
x=1
7-5y=35
-5y=28
y=28/5(1,28/5)
-5y=35
y=-7(0,-7)
y=0
7x=35
x=5(5,0)
x=1
7-5y=35
-5y=28
y=28/5(1,28/5)
Answered by
31
1) if x= 5 and y= 0
then LHS= 7×5-5×0=35
LHS= RHS
2) if x=0 and y=-7
LHS= 7×0-5×(-7)= 35
LHS= RHS
3)x=10 and y= 7
LHS= 70-35=35
LHS=RHS
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then LHS= 7×5-5×0=35
LHS= RHS
2) if x=0 and y=-7
LHS= 7×0-5×(-7)= 35
LHS= RHS
3)x=10 and y= 7
LHS= 70-35=35
LHS=RHS
_____________________________________
please mark me brainliest
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