Question

Find three solutions of the linear equation 2(x+1) = 3(y–1)–4 and check whether point (–3, 1) lies on the line

Answer 1

Answer:

(3,5) , (6,7) and (9,9)

(-3,1) lies on the line.

Step-by-step explanation:

equation given, 2(x+1) = 3(y–1)–4

=> 2x + 2 = 3y - 3 - 4

=> 3y = 2x + 9 -----------1

now to find solutions,

putting random x values in eq 1

for x = 3 , 3y = 15 => y = 5

for x = 6 , 3y = 21 => y = 7

for x= 9 , 3y = 27 => y = 9

so three solutions of equation are

(3,5) , (6,7) and (9,9)

now checking for point (-3, 1),

putting x = -3 in eq 1, 3y = 3 => y = 1

So , (-3,1) lies on the line.