Question

Find three solutions of the linear equation 3x + 2y + 12 = 0​

Answer 1

Step-by-step explanation:

Given equation is 3x+2y+12=0

1)Put x = 0 then, =>3(0)+2y+12=0

=>0+2y+12=0

=>2y+12=0

=> 2y=-12

=>y=-12/2

=>y= -6

The solution is (0,-6)

2)Put y =0 then, 3x+2(0)+12=0

=> 3x+0+12=0

=> 3x+12=0

=> 3x=-12

=>x = -12/3

=>x= -4

The solution is (-4,0)

3) Put x= 2 then, 3(2)+2y+12=0

=> 6+2y+12=0

=> 2y+18=0

=>2y = -18

=> y= -18/2

=> y = -9

The Solution is (2,-9)