find three terms in AP whose sum is 36 and product is 1620
Answers
Answered by
0
Step-by-step explanation:
Let 3 term a-d a a+d
Now according to question
a-d+a+a+d = 36
So
a = 12
(a-d) a(a+d) = 1620
asquare - dsquare =. 1620/12
144 - dsquare =135
Here
d = 3
1 St term is 9
2nd term is. 12
3rd term is 15
Answered by
1
Let the terms be x , x+3 and x+6
ATQ,
x + x+3 + x+6 = 36
> 3x + 9 = 36
> 3x = 27
> x = 9
> x + 3 = 12
> x + 6 = 15
ATQ,
x + x+3 + x+6 = 36
> 3x + 9 = 36
> 3x = 27
> x = 9
> x + 3 = 12
> x + 6 = 15
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