Question

Find three terms of gp whose sum is 63 and product is 1728

Answer 1

Answer: The gp is 3,12,48

Step-by-step explanation:

Let the three terms be a/r,a,ar

Where the first term is "a" and the common difference is "r"

Therefore,

Product=> a/r *a*ar=1728

=>a=12

Sum =63 (given)

a/r +a+ar=63...... (i)

we know,

a=12

Now,

Putting the value of a in (i)

12/r +12+12r=63

=> (12 +12r+12r^2)/r=63r

=> 12 +12r+12r^2=63r

=>12r^2 -51r+12=0

=> 12r^2-48r-3r+12=0

=> 12r (r-4)-3 (r-4)=0

=> (12r-3)(r-4)=0

We can say.

12r-3=0 or r-4=0

r=4 (in both cases)

So the gp is a/r,a,ar

12/4,12,12*4

3,12,48 (Answer)

Answer 2

Answer:

Step-by-step explanation: