Question

Find time of flight of projectile thrown horizontally with speed 50m/s from a inclined plane which makes 45 degree with horizontal

Answer 1

Horizontal distance travelled equals vertical distance travelled

Horizintal motion-

accleration=0

velocity=50m/s(constant)

vetical distance=x(say)

speed=distance/time

time=x/50

t2=x2/2500-------Eqn(1)

Vertical motion-

accln=g

velocity(initial)=0

s=ut+gt2/2

x=10t2/2

t2=2x/10--------Eqn(2)

from Eqn(1) and Eqn(2)

x2/2500=2x/10

x/2500=1/5

x=2500/5=500

Now t=x/50

t=500/50=10sec