Math, asked by Elishba, 1 year ago

Find tje value of p(x) = 5x^2-3x+7
At x = 2

Answers

Answered by rohit600
2
5*4-6+7=21 is the ans to your question mate..
hope it helps you...

Elishba: Correct!!! And thn
Elishba: Thanx
rohit600: if it helps then mark thank you please....
Answered by shakti1234
0
p(2)=5(2)^2-3(2)+7
p(2)=5×4-6+7
p(2)=20-6+7
p(2)=27-6
p(2)=21
hope it helps
mark it as brainliest
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