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Final Answer : Magnitude of Current through batteris will be
106/37 A and 84/37 A,
Understanding :
1) Kirchoffs law.
Steps:
1) Let the current through batteries be I(1) and I(2) .
By applying Kirchoffs law to the point O.
The Current passing through external resistance will be I(1) + I(2) .
2) Two equations after applying kirchoffs law,
25I(1) + 24I(2) = 12 ------(1)
12I(1) + 13I(2) = 10----(2)
3) After solving these,
I(1) = -84/37 and I(2) = 106/37 .
The negative sign in I(1) represents that the current in the battery is opposite to the given direction.
Final Answer : Magnitude of Current through batteris will be
106/37 A and 84/37 A,
Understanding :
1) Kirchoffs law.
Steps:
1) Let the current through batteries be I(1) and I(2) .
By applying Kirchoffs law to the point O.
The Current passing through external resistance will be I(1) + I(2) .
2) Two equations after applying kirchoffs law,
25I(1) + 24I(2) = 12 ------(1)
12I(1) + 13I(2) = 10----(2)
3) After solving these,
I(1) = -84/37 and I(2) = 106/37 .
The negative sign in I(1) represents that the current in the battery is opposite to the given direction.
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