Question

find to the nearest rupee, the amount and the compound interest on rupees 9000 for 1 1/2 years at 8% perannnum the interest being compound half yearly
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Answer 1

Answer:

Amount after 1 1/2 year =

$9000 \times (1 + \frac{4}{100} ) {}^{3} = \\ 9000 \times \frac{26}{25} \times \frac{26}{25} \times \frac{26}{25} = 10123.776 \\ compound \: interest = 10123.776 - 9000 \\ = 1123.776$

Answer 2

Answer:

Answer is → Amount = Rs 10124 and Compound Interest= Rs 1124

Step-by-step explanation:

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