Question

Find total no. of electron present in 30g urea

Answer 1

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There are five orbitals which have the same value of (n + l) = 5. These are the 5s, 4p and 3d orbitals. For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2.

For the 4p orbital, n = 4 and l = 1, therefore (n + l) = 5. As a p subshell has three orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 4p orbital would be 6.

For the 3d orbital, n = 3 and  l = 2, therefore (n + l) = 5. As a d subshell has five orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5d orbital would be 10.