Question

Find total no of electrons present in 48g of Mg++

Answer 1

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Answer 2

Answer:20 NA

Explanation:

Let,

24gm of magnesium contains N

A

​

 atoms

∴48gm magnesium contains=2N

A

​

 atoms

Mg

2+

 ion wil contain =12−2=10 electron

Hence, 2N

A

​

 Mg

2+

-ions will contain =10×2=20N

A

​

 electrons