Find Total resistance between A & B. Please also Solve it.
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Answered by
1
Answer:
In the given circuit, suppose, r=10Ω
r
1
=10Ω
r
2
=20Ω
and, r
3
=50Ω
(Please refer the diagram.)
Now, r
1
,r
2
,r
3
are connected in parallel. Suppose, resultant of these three resistances is R
e
.
Therefore,
r
e
1
=
r
1
1
+
r
2
1
+
r
3
1
=
10
1
+
20
1
+
50
1
=
100
17
Hence, r
e
=
17
100
Ω
Now, resistances r and r
e
are connected in series.
Therefore, equivalent resistance in the given circuit, R=r+r
e
R=10+
17
100
=
17
270
Ω, which is more than 10Ω, but less than 20Ω.
Answered by
1
Answer:
14.41 ohm
Explanation:
R1 & R2 in series combination
So equalient resistance is
Req= R1 + R2
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